Base | Representation |
---|---|
bin | 100111011001010100110… |
… | …0011000001111010001001 |
3 | 201011121210001020202112002 |
4 | 1032302221203001322021 |
5 | 1202202400322402241 |
6 | 15303215525200345 |
7 | 1066120303615346 |
oct | 116625143017211 |
9 | 21147701222462 |
10 | 5414503325321 |
11 | 17a8306a75932 |
12 | 73544a2600b5 |
13 | 30377c38bcbc |
14 | 14a0c5c017cd |
15 | 95c9c52189b |
hex | 4eca98c1e89 |
5414503325321 has 4 divisors (see below), whose sum is σ = 5589164722944. Its totient is φ = 5239841927700.
The previous prime is 5414503325279. The next prime is 5414503325333. The reversal of 5414503325321 is 1235233054145.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5414503325321 - 222 = 5414499131017 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5414503325221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87330698765 + ... + 87330698826.
It is an arithmetic number, because the mean of its divisors is an integer number (1397291180736).
Almost surely, 25414503325321 is an apocalyptic number.
It is an amenable number.
5414503325321 is a deficient number, since it is larger than the sum of its proper divisors (174661397623).
5414503325321 is a wasteful number, since it uses less digits than its factorization.
5414503325321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174661397622.
The product of its (nonzero) digits is 216000, while the sum is 38.
Adding to 5414503325321 its reverse (1235233054145), we get a palindrome (6649736379466).
The spelling of 5414503325321 in words is "five trillion, four hundred fourteen billion, five hundred three million, three hundred twenty-five thousand, three hundred twenty-one".
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