Base | Representation |
---|---|
bin | 111101100111100100111110… |
… | …1101010011000001001000001 |
3 | 2122002001210212022110110200212 |
4 | 1323033021331222120021001 |
5 | 1032020121440032243403 |
6 | 5200423530303323505 |
7 | 222110203164614024 |
oct | 17317117552301101 |
9 | 2562053768413625 |
10 | 542001211212353 |
11 | 147775471872472 |
12 | 50957570bb0595 |
13 | 1a3576584115c9 |
14 | 97badda1d31bb |
15 | 429da66aea4d8 |
hex | 1ecf27da98241 |
542001211212353 has 32 divisors (see below), whose sum is σ = 591742853049600. Its totient is φ = 494850700624896.
The previous prime is 542001211212299. The next prime is 542001211212361. The reversal of 542001211212353 is 353212112100245.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-542001211212353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (542001211212553) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 350836301 + ... + 352377797.
It is an arithmetic number, because the mean of its divisors is an integer number (18491964157800).
Almost surely, 2542001211212353 is an apocalyptic number.
It is an amenable number.
542001211212353 is a deficient number, since it is larger than the sum of its proper divisors (49741641837247).
542001211212353 is a wasteful number, since it uses less digits than its factorization.
542001211212353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1547561.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 542001211212353 its reverse (353212112100245), we get a palindrome (895213323312598).
The spelling of 542001211212353 in words is "five hundred forty-two trillion, one billion, two hundred eleven million, two hundred twelve thousand, three hundred fifty-three".
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