Base | Representation |
---|---|
bin | 1111110001100101110… |
… | …11101111011110101001 |
3 | 1220211001100000020222002 |
4 | 13320302323233132221 |
5 | 32340024210313230 |
6 | 1053000054140345 |
7 | 54105525251303 |
oct | 7706273573651 |
9 | 1824040006862 |
10 | 542020401065 |
11 | 199962427790 |
12 | 890696516b5 |
13 | 3c15c96b510 |
14 | 1c33bc7a973 |
15 | e174bac545 |
hex | 7e32eef7a9 |
542020401065 has 64 divisors (see below), whose sum is σ = 774779765760. Its totient is φ = 358816573440.
The previous prime is 542020401059. The next prime is 542020401107. The reversal of 542020401065 is 560104020245.
It is not a de Polignac number, because 542020401065 - 24 = 542020401049 is a prime.
It is a super-3 number, since 3×5420204010653 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 48402047 + ... + 48413243.
It is an arithmetic number, because the mean of its divisors is an integer number (12105933840).
Almost surely, 2542020401065 is an apocalyptic number.
542020401065 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
542020401065 is a deficient number, since it is larger than the sum of its proper divisors (232759364695).
542020401065 is a wasteful number, since it uses less digits than its factorization.
542020401065 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12162.
The product of its (nonzero) digits is 9600, while the sum is 29.
The spelling of 542020401065 in words is "five hundred forty-two billion, twenty million, four hundred one thousand, sixty-five".
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