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54203411434 = 227101705717
BaseRepresentation
bin110010011110110001…
…100110101111101010
312011220112021121002211
4302132301212233222
51342002033131214
640522315115334
73626132252404
oct623661465752
9164815247084
1054203411434
1120a9545a2a7
12a608742b4a
13515a871423
1428a2ab3b74
1516238ea0c4
hexc9ec66bea

54203411434 has 4 divisors (see below), whose sum is σ = 81305117154. Its totient is φ = 27101705716.

The previous prime is 54203411419. The next prime is 54203411459. The reversal of 54203411434 is 43411430245.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 46204792209 + 7998619225 = 214953^2 + 89435^2 .

It is a super-2 number, since 2×542034114342 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 54203411396 and 54203411405.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13550852857 + ... + 13550852860.

Almost surely, 254203411434 is an apocalyptic number.

54203411434 is a deficient number, since it is larger than the sum of its proper divisors (27101705720).

54203411434 is a wasteful number, since it uses less digits than its factorization.

54203411434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27101705719.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 54203411434 its reverse (43411430245), we get a palindrome (97614841679).

The spelling of 54203411434 in words is "fifty-four billion, two hundred three million, four hundred eleven thousand, four hundred thirty-four".

Divisors: 1 2 27101705717 54203411434