Base | Representation |
---|---|
bin | 100111011100011111101… |
… | …0100110000010110111011 |
3 | 201012021100111100020011111 |
4 | 1032320333110300112323 |
5 | 1202310321122224430 |
6 | 15310303240141151 |
7 | 1066451100206443 |
oct | 116707724602673 |
9 | 21167314306144 |
10 | 5421311133115 |
11 | 180018a88a669 |
12 | 73682a1677b7 |
13 | 3042c5912737 |
14 | 14a57000d123 |
15 | 9604a024c2a |
hex | 4ee3f5305bb |
5421311133115 has 4 divisors (see below), whose sum is σ = 6505573359744. Its totient is φ = 4337048906488.
The previous prime is 5421311133103. The next prime is 5421311133137. The reversal of 5421311133115 is 5113311131245.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5421311133115 - 27 = 5421311132987 is a prime.
It is a super-2 number, since 2×54213111331152 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 542131113307 + ... + 542131113316.
It is an arithmetic number, because the mean of its divisors is an integer number (1626393339936).
Almost surely, 25421311133115 is an apocalyptic number.
5421311133115 is a deficient number, since it is larger than the sum of its proper divisors (1084262226629).
5421311133115 is a wasteful number, since it uses less digits than its factorization.
5421311133115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1084262226628.
The product of its digits is 5400, while the sum is 31.
The spelling of 5421311133115 in words is "five trillion, four hundred twenty-one billion, three hundred eleven million, one hundred thirty-three thousand, one hundred fifteen".
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