Base | Representation |
---|---|
bin | 1111110010010101111… |
… | …00000111001010001001 |
3 | 1220212002101212002100021 |
4 | 13321022330013022021 |
5 | 32341340311314431 |
6 | 1053104042340441 |
7 | 54121515466126 |
oct | 7711274071211 |
9 | 1825071762307 |
10 | 542423151241 |
11 | 19a049800974 |
12 | 891604ba721 |
13 | 3c1c523382a |
14 | 1c37955974d |
15 | e19a215b11 |
hex | 7e4af07289 |
542423151241 has 4 divisors (see below), whose sum is σ = 542424777984. Its totient is φ = 542421524500.
The previous prime is 542423151199. The next prime is 542423151287. The reversal of 542423151241 is 142151324245.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 542423151241 - 213 = 542423143049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 542423151197 and 542423151206.
It is not an unprimeable number, because it can be changed into a prime (542423151041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111085 + ... + 1047466.
It is an arithmetic number, because the mean of its divisors is an integer number (135606194496).
Almost surely, 2542423151241 is an apocalyptic number.
It is an amenable number.
542423151241 is a deficient number, since it is larger than the sum of its proper divisors (1626743).
542423151241 is a wasteful number, since it uses less digits than its factorization.
542423151241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1626742.
The product of its digits is 38400, while the sum is 34.
Adding to 542423151241 its reverse (142151324245), we get a palindrome (684574475486).
The spelling of 542423151241 in words is "five hundred forty-two billion, four hundred twenty-three million, one hundred fifty-one thousand, two hundred forty-one".
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