Base | Representation |
---|---|
bin | 11000101010101011101110… |
… | …10001011110010001101111 |
3 | 21010001121000220101200121011 |
4 | 30111111313101132101233 |
5 | 24102204424110102401 |
6 | 311210542250450051 |
7 | 14265636436311163 |
oct | 1425256721362157 |
9 | 233047026350534 |
10 | 54243143050351 |
11 | 1631342a155172 |
12 | 6100826a33927 |
13 | 243614cb0c228 |
14 | d5754c7d8ca3 |
15 | 640ec6975451 |
hex | 31557745e46f |
54243143050351 has 4 divisors (see below), whose sum is σ = 54375766872400. Its totient is φ = 54110519228304.
The previous prime is 54243143050331. The next prime is 54243143050457. The reversal of 54243143050351 is 15305034134245.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54243143050351 - 27 = 54243143050223 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54243143050301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66311910411 + ... + 66311911228.
It is an arithmetic number, because the mean of its divisors is an integer number (13593941718100).
Almost surely, 254243143050351 is an apocalyptic number.
54243143050351 is a deficient number, since it is larger than the sum of its proper divisors (132623822049).
54243143050351 is a wasteful number, since it uses less digits than its factorization.
54243143050351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132623822048.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 54243143050351 its reverse (15305034134245), we get a palindrome (69548177184596).
The spelling of 54243143050351 in words is "fifty-four trillion, two hundred forty-three billion, one hundred forty-three million, fifty thousand, three hundred fifty-one".
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