Base | Representation |
---|---|
bin | 11000101010111001010100… |
… | …10001110000000011001111 |
3 | 21010002021212112011201102120 |
4 | 30111130222101300003033 |
5 | 24102314400422241421 |
6 | 311214150355424023 |
7 | 14266315335542544 |
oct | 1425345221600317 |
9 | 233067775151376 |
10 | 54250441212111 |
11 | 16316534838111 |
12 | 6102122bb5013 |
13 | 2436a43b1b341 |
14 | d57a41baabcb |
15 | 6412a25388c6 |
hex | 31572a4700cf |
54250441212111 has 16 divisors (see below), whose sum is σ = 72416446384128. Its totient is φ = 36125706405600.
The previous prime is 54250441212103. The next prime is 54250441212113. The reversal of 54250441212111 is 11121214405245.
It is not a de Polignac number, because 54250441212111 - 23 = 54250441212103 is a prime.
It is a super-2 number, since 2×542504412121112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54250441212113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26337826 + ... + 28322816.
It is an arithmetic number, because the mean of its divisors is an integer number (4526027899008).
Almost surely, 254250441212111 is an apocalyptic number.
54250441212111 is a deficient number, since it is larger than the sum of its proper divisors (18166005172017).
54250441212111 is a wasteful number, since it uses less digits than its factorization.
54250441212111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1995382.
The product of its (nonzero) digits is 12800, while the sum is 33.
Adding to 54250441212111 its reverse (11121214405245), we get a palindrome (65371655617356).
The spelling of 54250441212111 in words is "fifty-four trillion, two hundred fifty billion, four hundred forty-one million, two hundred twelve thousand, one hundred eleven".
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