543011452541203 has 4 divisors (see below), whose sum is σ = 553256951645808. Its totient is φ = 532765953436600.

The previous prime is 543011452541171. The next prime is 543011452541213. The reversal of 543011452541203 is 302145254110345.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 543011452541203 - 2⁵ = 543011452541171 is a prime.

It is a super-2 number, since 2×543011452541203² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (543011452541213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5122749552223 + ... + 5122749552328.

It is an arithmetic number, because the mean of its divisors is an integer number (138314237911452).

Almost surely, 2^{543011452541203} is an apocalyptic number.

543011452541203 is a gapful number since it is divisible by the number (53) formed by its first and last digit.

543011452541203 is a deficient number, since it is larger than the sum of its proper divisors (10245499104605).

543011452541203 is a wasteful number, since it uses less digits than its factorization.

543011452541203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10245499104604.

The product of its (nonzero) digits is 288000, while the sum is 40.

The spelling of 543011452541203 in words is "five hundred forty-three trillion, eleven billion, four hundred fifty-two million, five hundred forty-one thousand, two hundred three".