Base | Representation |
---|---|
bin | 110010100100101111… |
… | …001010000110101011 |
3 | 12012011111111020002010 |
4 | 302210233022012223 |
5 | 1342203134330011 |
6 | 40540251011003 |
7 | 3631455365013 |
oct | 624457120653 |
9 | 165144436063 |
10 | 54303433131 |
11 | 21036966062 |
12 | a636139a63 |
13 | 51754c1a6c |
14 | 28b20acc43 |
15 | 162c5a61a6 |
hex | ca4bca1ab |
54303433131 has 4 divisors (see below), whose sum is σ = 72404577512. Its totient is φ = 36202288752.
The previous prime is 54303433127. The next prime is 54303433193. The reversal of 54303433131 is 13133430345.
54303433131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 54303433131 - 22 = 54303433127 is a prime.
It is a super-2 number, since 2×543034331312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54303433111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9050572186 + ... + 9050572191.
It is an arithmetic number, because the mean of its divisors is an integer number (18101144378).
Almost surely, 254303433131 is an apocalyptic number.
54303433131 is a deficient number, since it is larger than the sum of its proper divisors (18101144381).
54303433131 is a wasteful number, since it uses less digits than its factorization.
54303433131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18101144380.
The product of its (nonzero) digits is 19440, while the sum is 30.
Adding to 54303433131 its reverse (13133430345), we get a palindrome (67436863476).
The spelling of 54303433131 in words is "fifty-four billion, three hundred three million, four hundred thirty-three thousand, one hundred thirty-one".
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