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5431216121345 = 57157998275873
BaseRepresentation
bin100111100001000110110…
…1101010010011000000001
3201020012220210022202122102
41033002031231102120001
51202441112311340340
615315022150320145
71100251412213240
oct117021555223001
921205823282572
105431216121345
1118044029aa953
12738733359055
13305213a14a11
1414ac2d6bc957
15964298b6215
hex4f08db52601

5431216121345 has 16 divisors (see below), whose sum is σ = 7453242284160. Its totient is φ = 3721903824384.

The previous prime is 5431216121327. The next prime is 5431216121431.

5431216121345 is nontrivially palindromic in base 10.

It is a cyclic number.

It is not a de Polignac number, because 5431216121345 - 214 = 5431216104961 is a prime.

It is a super-4 number, since 4×54312161213454 (a number of 52 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5431216121299 and 5431216121308.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49082672 + ... + 49193201.

It is an arithmetic number, because the mean of its divisors is an integer number (465827642760).

Almost surely, 25431216121345 is an apocalyptic number.

It is an amenable number.

5431216121345 is a deficient number, since it is larger than the sum of its proper divisors (2022026162815).

5431216121345 is a wasteful number, since it uses less digits than its factorization.

5431216121345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98277464.

The product of its digits is 86400, while the sum is 38.

The spelling of 5431216121345 in words is "five trillion, four hundred thirty-one billion, two hundred sixteen million, one hundred twenty-one thousand, three hundred forty-five".

Divisors: 1 5 7 35 1579 7895 11053 55265 98275873 491379365 687931111 3439655555 155177603467 775888017335 1086243224269 5431216121345