Base | Representation |
---|---|
bin | 100111100001000110110… |
… | …1101010010011000000001 |
3 | 201020012220210022202122102 |
4 | 1033002031231102120001 |
5 | 1202441112311340340 |
6 | 15315022150320145 |
7 | 1100251412213240 |
oct | 117021555223001 |
9 | 21205823282572 |
10 | 5431216121345 |
11 | 18044029aa953 |
12 | 738733359055 |
13 | 305213a14a11 |
14 | 14ac2d6bc957 |
15 | 964298b6215 |
hex | 4f08db52601 |
5431216121345 has 16 divisors (see below), whose sum is σ = 7453242284160. Its totient is φ = 3721903824384.
The previous prime is 5431216121327. The next prime is 5431216121431.
5431216121345 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 5431216121345 - 214 = 5431216104961 is a prime.
It is a super-4 number, since 4×54312161213454 (a number of 52 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5431216121299 and 5431216121308.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49082672 + ... + 49193201.
It is an arithmetic number, because the mean of its divisors is an integer number (465827642760).
Almost surely, 25431216121345 is an apocalyptic number.
It is an amenable number.
5431216121345 is a deficient number, since it is larger than the sum of its proper divisors (2022026162815).
5431216121345 is a wasteful number, since it uses less digits than its factorization.
5431216121345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98277464.
The product of its digits is 86400, while the sum is 38.
The spelling of 5431216121345 in words is "five trillion, four hundred thirty-one billion, two hundred sixteen million, one hundred twenty-one thousand, three hundred forty-five".
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