Base | Representation |
---|---|
bin | 1111110011101101110… |
… | …11011001011010000010 |
3 | 1220220222211112212212212 |
4 | 13321312323121122002 |
5 | 32344343224130341 |
6 | 1053305204422122 |
7 | 54146016460106 |
oct | 7716673313202 |
9 | 1826884485785 |
10 | 543161161346 |
11 | 19a398351881 |
12 | 893276a7942 |
13 | 3c2b20c0abb |
14 | 1c409589906 |
15 | e1dede55eb |
hex | 7e76ed9682 |
543161161346 has 4 divisors (see below), whose sum is σ = 814741742022. Its totient is φ = 271580580672.
The previous prime is 543161161343. The next prime is 543161161349. The reversal of 543161161346 is 643161161345.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (543161161343) and next prime (543161161349).
It can be written as a sum of positive squares in only one way, i.e., 529604052121 + 13557109225 = 727739^2 + 116435^2 .
It is not an unprimeable number, because it can be changed into a prime (543161161343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 135790290335 + ... + 135790290338.
Almost surely, 2543161161346 is an apocalyptic number.
543161161346 is a deficient number, since it is larger than the sum of its proper divisors (271580580676).
543161161346 is a wasteful number, since it uses less digits than its factorization.
543161161346 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 271580580675.
The product of its digits is 155520, while the sum is 41.
Subtracting 543161161346 from its reverse (643161161345), we obtain a palindrome (99999999999).
The spelling of 543161161346 in words is "five hundred forty-three billion, one hundred sixty-one million, one hundred sixty-one thousand, three hundred forty-six".
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