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54317052301261 = 415800113063261
BaseRepresentation
bin11000101100110101011001…
…00110111000111111001101
321010022122210202200122120111
430112122230212320333031
524104412310342120021
6311304524230320021
714304164122501621
oct1426325446707715
9233278722618514
1054317052301261
1116341806a88312
126113012ab9011
1324400cb1233a9
14d5ad606a1181
15642da03828e1
hex3166ac9b8fcd

54317052301261 has 4 divisors (see below), whose sum is σ = 54317069522524. Its totient is φ = 54317035080000.

The previous prime is 54317052301247. The next prime is 54317052301271. The reversal of 54317052301261 is 16210325071345.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 39087428976036 + 15229623325225 = 6251994^2 + 3902515^2 .

It is a cyclic number.

It is not a de Polignac number, because 54317052301261 - 223 = 54317043912653 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54317052301271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2373630 + ... + 10689631.

It is an arithmetic number, because the mean of its divisors is an integer number (13579267380631).

Almost surely, 254317052301261 is an apocalyptic number.

It is an amenable number.

54317052301261 is a deficient number, since it is larger than the sum of its proper divisors (17221263).

54317052301261 is a wasteful number, since it uses less digits than its factorization.

54317052301261 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17221262.

The product of its (nonzero) digits is 151200, while the sum is 40.

The spelling of 54317052301261 in words is "fifty-four trillion, three hundred seventeen billion, fifty-two million, three hundred one thousand, two hundred sixty-one".

Divisors: 1 4158001 13063261 54317052301261