Base | Representation |
---|---|
bin | 1010000111100010… |
… | …11111101001001010 |
3 | 112000120021222022211 |
4 | 11003301133221022 |
5 | 42111043443214 |
6 | 2255002535334 |
7 | 251416240456 |
oct | 50361375112 |
9 | 15016258284 |
10 | 5432015434 |
11 | 233825a65a |
12 | 107720754a |
13 | 6874cc621 |
14 | 3975db666 |
15 | 21bd410c4 |
hex | 143c5fa4a |
5432015434 has 4 divisors (see below), whose sum is σ = 8148023154. Its totient is φ = 2716007716.
The previous prime is 5432015417. The next prime is 5432015441. The reversal of 5432015434 is 4345102345.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4345102345 = 5 ⋅869020469.
It can be written as a sum of positive squares in only one way, i.e., 5140459809 + 291555625 = 71697^2 + 17075^2 .
It is a junction number, because it is equal to n+sod(n) for n = 5432015396 and 5432015405.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1358003857 + ... + 1358003860.
Almost surely, 25432015434 is an apocalyptic number.
5432015434 is a deficient number, since it is larger than the sum of its proper divisors (2716007720).
5432015434 is a wasteful number, since it uses less digits than its factorization.
5432015434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2716007719.
The product of its (nonzero) digits is 28800, while the sum is 31.
The square root of 5432015434 is about 73702.2077959677. The cubic root of 5432015434 is about 1757.8709873258.
Adding to 5432015434 its reverse (4345102345), we get a palindrome (9777117779).
The spelling of 5432015434 in words is "five billion, four hundred thirty-two million, fifteen thousand, four hundred thirty-four".
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