54331313540533 has 4 divisors (see below), whose sum is σ = 54331337908908. Its totient is φ = 54331289172160.

The previous prime is 54331313540417. The next prime is 54331313540549. The reversal of 54331313540533 is 33504531313345.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 41890900293124 + 12440413247409 = 6472318^2 + 3527097^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-54331313540533 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 54331313540533.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54331313540563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8460466 + ... + 13425427.

It is an arithmetic number, because the mean of its divisors is an integer number (13582834477227).

Almost surely, 2^{54331313540533} is an apocalyptic number.

It is an amenable number.

54331313540533 is a deficient number, since it is larger than the sum of its proper divisors (24368375).

54331313540533 is a wasteful number, since it uses less digits than its factorization.

54331313540533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24368374.

The product of its (nonzero) digits is 1458000, while the sum is 43.

Adding to 54331313540533 its reverse (33504531313345), we get a palindrome (87835844853878).

The spelling of 54331313540533 in words is "fifty-four trillion, three hundred thirty-one billion, three hundred thirteen million, five hundred forty thousand, five hundred thirty-three".