54333444433345 has 32 divisors (see below), whose sum is σ = 84822759567360. Its totient is φ = 32397581768640.

The previous prime is 54333444433337. The next prime is 54333444433357.

54333444433345 is nontrivially palindromic in base 10.

54333444433345 is digitally balanced in base 6, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 54333444433345 - 2³ = 54333444433337 is a prime.

It is a super-3 number, since 3×54333444433345³ (a number of 42 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 54333444433292 and 54333444433301.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3067943965 + ... + 3067961674.

It is an arithmetic number, because the mean of its divisors is an integer number (2650711236480).

Almost surely, 2^{54333444433345} is an apocalyptic number.

54333444433345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

It is an amenable number.

54333444433345 is a deficient number, since it is larger than the sum of its proper divisors (30489315134015).

54333444433345 is a wasteful number, since it uses less digits than its factorization.

54333444433345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6135905685.

The product of its digits is 74649600, while the sum is 52.

It can be divided in two parts, 5433344 and 4433345, that added together give a palindrome (9866689).

The spelling of 54333444433345 in words is "fifty-four trillion, three hundred thirty-three billion, four hundred forty-four million, four hundred thirty-three thousand, three hundred forty-five".