Base | Representation |
---|---|
bin | 100111100010001000110… |
… | …0011110111001110010001 |
3 | 201020102121221211012112212 |
4 | 1033010101203313032101 |
5 | 1203010130112241340 |
6 | 15320025452001505 |
7 | 1100360263020434 |
oct | 117042143671621 |
9 | 21212557735485 |
10 | 5433428243345 |
11 | 1805338659953 |
12 | 739050160295 |
13 | 3054a70cba4b |
14 | 14ad9d3d381b |
15 | 96508bc9a65 |
hex | 4f1118f7391 |
5433428243345 has 16 divisors (see below), whose sum is σ = 6552953142480. Its totient is φ = 4324892236800.
The previous prime is 5433428243339. The next prime is 5433428243359.
5433428243345 is nontrivially palindromic in base 10.
It can be written as a sum of positive squares in 8 ways, for example, as 507154773904 + 4926273469441 = 712148^2 + 2219521^2 .
It is not a de Polignac number, because 5433428243345 - 24 = 5433428243329 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5433428243293 and 5433428243302.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1630676 + ... + 3677765.
It is an arithmetic number, because the mean of its divisors is an integer number (409559571405).
Almost surely, 25433428243345 is an apocalyptic number.
It is an amenable number.
5433428243345 is a deficient number, since it is larger than the sum of its proper divisors (1119524899135).
5433428243345 is a wasteful number, since it uses less digits than its factorization.
5433428243345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5309476.
The product of its digits is 16588800, while the sum is 50.
The spelling of 5433428243345 in words is "five trillion, four hundred thirty-three billion, four hundred twenty-eight million, two hundred forty-three thousand, three hundred forty-five".
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