Search a number
-
+
54336041116117 = 85939363226069
BaseRepresentation
bin11000101101011000110000…
…11011011110000111010101
321010101110211010111101120121
430112230120123132013111
524110220203011203432
6311321344354431541
714305435515661105
oct1426543033360725
9233343733441517
1054336041116117
1116349870743a32
1261168322925b1
132441b36175a07
14d5bc42567205
1564361245d197
hex316b186de1d5

54336041116117 has 4 divisors (see below), whose sum is σ = 54336105201580. Its totient is φ = 54335977030656.

The previous prime is 54336041116111. The next prime is 54336041116157. The reversal of 54336041116117 is 71161114063345.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 27747672971236 + 26588368144881 = 5267606^2 + 5156391^2 .

It is a cyclic number.

It is not a de Polignac number, because 54336041116117 - 23 = 54336041116109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54336041116111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30753642 + ... + 32472427.

It is an arithmetic number, because the mean of its divisors is an integer number (13584026300395).

Almost surely, 254336041116117 is an apocalyptic number.

It is an amenable number.

54336041116117 is a deficient number, since it is larger than the sum of its proper divisors (64085463).

54336041116117 is an equidigital number, since it uses as much as digits as its factorization.

54336041116117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64085462.

The product of its (nonzero) digits is 181440, while the sum is 43.

The spelling of 54336041116117 in words is "fifty-four trillion, three hundred thirty-six billion, forty-one million, one hundred sixteen thousand, one hundred seventeen".

Divisors: 1 859393 63226069 54336041116117