Base | Representation |
---|---|
bin | 11000101101100110111011… |
… | …00111101110000110000001 |
3 | 21010102012110000102112200222 |
4 | 30112303131213232012001 |
5 | 24110331240431444040 |
6 | 311325043043352425 |
7 | 14306125111611323 |
oct | 1426633547560601 |
9 | 233365400375628 |
10 | 54343644406145 |
11 | 163520125932a6 |
12 | 61181b4682715 |
13 | 2442778459bb3 |
14 | d5c364285613 |
15 | 643909be4bb5 |
hex | 316cdd9ee181 |
54343644406145 has 8 divisors (see below), whose sum is σ = 67315998232320. Its totient is φ = 42072498894960.
The previous prime is 54343644406111. The next prime is 54343644406151. The reversal of 54343644406145 is 54160444634345.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 54343644406145 - 212 = 54343644402049 is a prime.
It is a super-2 number, since 2×543436444061452 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 175302078575 + ... + 175302078884.
It is an arithmetic number, because the mean of its divisors is an integer number (8414499779040).
Almost surely, 254343644406145 is an apocalyptic number.
It is an amenable number.
54343644406145 is a deficient number, since it is larger than the sum of its proper divisors (12972353826175).
54343644406145 is a wasteful number, since it uses less digits than its factorization.
54343644406145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 350604157495.
The product of its (nonzero) digits is 33177600, while the sum is 53.
The spelling of 54343644406145 in words is "fifty-four trillion, three hundred forty-three billion, six hundred forty-four million, four hundred six thousand, one hundred forty-five".
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