Base | Representation |
---|---|
bin | 11000101101100111111101… |
… | …10000000100110001111001 |
3 | 21010102020212202100001100222 |
4 | 30112303332300010301321 |
5 | 24110333410230304340 |
6 | 311325214141105425 |
7 | 14306144641300004 |
oct | 1426637660046171 |
9 | 233366782301328 |
10 | 54344200244345 |
11 | 16352278318810 |
12 | 611832a858275 |
13 | 244283666283b |
14 | d5c3b801453b |
15 | 64393d8dc8b5 |
hex | 316cfec04c79 |
54344200244345 has 32 divisors (see below), whose sum is σ = 71873574514560. Its totient is φ = 39118415616000.
The previous prime is 54344200244209. The next prime is 54344200244351.
54344200244345 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 54344200244345 - 212 = 54344200240249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54344200244296 and 54344200244305.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10835480 + ... + 15036489.
It is an arithmetic number, because the mean of its divisors is an integer number (2246049203580).
Almost surely, 254344200244345 is an apocalyptic number.
54344200244345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54344200244345 is a deficient number, since it is larger than the sum of its proper divisors (17529374270215).
54344200244345 is a wasteful number, since it uses less digits than its factorization.
54344200244345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25872377.
The product of its (nonzero) digits is 3686400, while the sum is 44.
It can be divided in two parts, 54344200 and 244345, that added together give a palindrome (54588545).
The spelling of 54344200244345 in words is "fifty-four trillion, three hundred forty-four billion, two hundred million, two hundred forty-four thousand, three hundred forty-five".
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