Base | Representation |
---|---|
bin | 110010101001000001… |
… | …100101110011110011 |
3 | 12012100111212012111020 |
4 | 302221001211303303 |
5 | 1342330043432232 |
6 | 40551340550523 |
7 | 3633321024240 |
oct | 625101456363 |
9 | 165314765436 |
10 | 54375374067 |
11 | 21073532383 |
12 | a656252443 |
13 | 518738cb71 |
14 | 28bb8785c7 |
15 | 1633a66e2c |
hex | ca9065cf3 |
54375374067 has 64 divisors (see below), whose sum is σ = 87827328000. Its totient is φ = 29231677440.
The previous prime is 54375374063. The next prime is 54375374083. The reversal of 54375374067 is 76047357345.
54375374067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 54375374067 - 22 = 54375374063 is a prime.
It is a super-2 number, since 2×543753740672 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (54375374063) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 46041217 + ... + 46042397.
It is an arithmetic number, because the mean of its divisors is an integer number (1372302000).
Almost surely, 254375374067 is an apocalyptic number.
54375374067 is a gapful number since it is divisible by the number (57) formed by its first and last digit.
54375374067 is a deficient number, since it is larger than the sum of its proper divisors (33451953933).
54375374067 is a wasteful number, since it uses less digits than its factorization.
54375374067 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1916.
The product of its (nonzero) digits is 7408800, while the sum is 51.
The spelling of 54375374067 in words is "fifty-four billion, three hundred seventy-five million, three hundred seventy-four thousand, sixty-seven".
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