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54397284503 = 311754751113
BaseRepresentation
bin110010101010010101…
…001011000010010111
312012102001002100221212
4302222111023002113
51342401201101003
640553442332035
73634005201122
oct625225130227
9165361070855
1054397284503
1121084937a81
12a66165a01b
13518ba91a13
1428c073d3b9
151635943dd8
hexcaa54b097

54397284503 has 4 divisors (see below), whose sum is σ = 56152035648. Its totient is φ = 52642533360.

The previous prime is 54397284479. The next prime is 54397284511. The reversal of 54397284503 is 30548279345.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30548279345 = 56109655869.

It is a cyclic number.

It is not a de Polignac number, because 54397284503 - 26 = 54397284439 is a prime.

It is a super-2 number, since 2×543972845032 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54397283503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 877375526 + ... + 877375587.

It is an arithmetic number, because the mean of its divisors is an integer number (14038008912).

Almost surely, 254397284503 is an apocalyptic number.

54397284503 is a deficient number, since it is larger than the sum of its proper divisors (1754751145).

54397284503 is a wasteful number, since it uses less digits than its factorization.

54397284503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1754751144.

The product of its (nonzero) digits is 3628800, while the sum is 50.

The spelling of 54397284503 in words is "fifty-four billion, three hundred ninety-seven million, two hundred eighty-four thousand, five hundred three".

Divisors: 1 31 1754751113 54397284503