Base | Representation |
---|---|
bin | 11000101111010001111101… |
… | …11011100010010000011111 |
3 | 21010121200210000000201001121 |
4 | 30113220332323202100133 |
5 | 24112301434030042333 |
6 | 311411305312151411 |
7 | 14313231154450444 |
oct | 1427507673422037 |
9 | 233550700021047 |
10 | 54401111565343 |
11 | 163744222765a4 |
12 | 6127372238567 |
13 | 24480062298ca |
14 | d610565b99cb |
15 | 64516edd132d |
hex | 317a3eee241f |
54401111565343 has 16 divisors (see below), whose sum is σ = 54715315749120. Its totient is φ = 54087828782400.
The previous prime is 54401111565293. The next prime is 54401111565389. The reversal of 54401111565343 is 34356511110445.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54401111565343 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 54401111565343.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54401111565643) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1672268988 + ... + 1672301518.
It is an arithmetic number, because the mean of its divisors is an integer number (3419707234320).
Almost surely, 254401111565343 is an apocalyptic number.
54401111565343 is a deficient number, since it is larger than the sum of its proper divisors (314204183777).
54401111565343 is a wasteful number, since it uses less digits than its factorization.
54401111565343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46398.
The product of its (nonzero) digits is 432000, while the sum is 43.
Adding to 54401111565343 its reverse (34356511110445), we get a palindrome (88757622675788).
The spelling of 54401111565343 in words is "fifty-four trillion, four hundred one billion, one hundred eleven million, five hundred sixty-five thousand, three hundred forty-three".
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