Base | Representation |
---|---|
bin | 11000101111010110000110… |
… | …10011000000100110001001 |
3 | 21010121220111202202021222210 |
4 | 30113223003103000212021 |
5 | 24112321011032431213 |
6 | 311412313522335333 |
7 | 14313340201464030 |
oct | 1427530323004611 |
9 | 233556452667883 |
10 | 54403332311433 |
11 | 16375361885a46 |
12 | 6127891aba549 |
13 | 244829b343151 |
14 | d611c74d7717 |
15 | 64524ed4a0c3 |
hex | 317ac34c0989 |
54403332311433 has 16 divisors (see below), whose sum is σ = 84137634053120. Its totient is φ = 30623624157456.
The previous prime is 54403332311413. The next prime is 54403332311437. The reversal of 54403332311433 is 33411323330445.
It is a happy number.
It is not a de Polignac number, because 54403332311433 - 25 = 54403332311401 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54403332311391 and 54403332311400.
It is not an unprimeable number, because it can be changed into a prime (54403332311437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19333094653 + ... + 19333097466.
It is an arithmetic number, because the mean of its divisors is an integer number (5258602128320).
Almost surely, 254403332311433 is an apocalyptic number.
It is an amenable number.
54403332311433 is a deficient number, since it is larger than the sum of its proper divisors (29734301741687).
54403332311433 is a wasteful number, since it uses less digits than its factorization.
54403332311433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38666192196.
The product of its (nonzero) digits is 466560, while the sum is 39.
Adding to 54403332311433 its reverse (33411323330445), we get a palindrome (87814655641878).
The spelling of 54403332311433 in words is "fifty-four trillion, four hundred three billion, three hundred thirty-two million, three hundred eleven thousand, four hundred thirty-three".
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