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54410054433 = 373467747319
BaseRepresentation
bin110010101011000101…
…111000101100100001
312012102221010011000020
4302223011320230201
51342412433220213
640555020144053
73634221555210
oct625305705441
9165387104006
1054410054433
112109106a239
12a665998029
1351916132a7
1428c2305077
151636b17923
hexcab178b21

54410054433 has 16 divisors (see below), whose sum is σ = 82934584320. Its totient is φ = 31082450256.

The previous prime is 54410054431. The next prime is 54410054449. The reversal of 54410054433 is 33445001445.

It is a happy number.

It is not a de Polignac number, because 54410054433 - 21 = 54410054431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 54410054394 and 54410054403.

It is not an unprimeable number, because it can be changed into a prime (54410054431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 300853 + ... + 446466.

It is an arithmetic number, because the mean of its divisors is an integer number (5183411520).

Almost surely, 254410054433 is an apocalyptic number.

It is an amenable number.

54410054433 is a deficient number, since it is larger than the sum of its proper divisors (28524529887).

54410054433 is a wasteful number, since it uses less digits than its factorization.

54410054433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 750796.

The product of its (nonzero) digits is 57600, while the sum is 33.

Adding to 54410054433 its reverse (33445001445), we get a palindrome (87855055878).

The spelling of 54410054433 in words is "fifty-four billion, four hundred ten million, fifty-four thousand, four hundred thirty-three".

Divisors: 1 3 7 21 3467 10401 24269 72807 747319 2241957 5231233 15693699 2590954973 7772864919 18136684811 54410054433