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54414101412131 = 241722513074643
BaseRepresentation
bin11000101111101010001010…
…01011110111100100100011
321010122221022021201021221012
430113311011023313210203
524113010034430142011
6311421254301451135
714314201105360046
oct1427650513674443
9233587267637835
1054414101412131
111637998874676a
126129998570aab
1324492c6485096
14d61929860c5d
156456804c9a8b
hex317d452f7923

54414101412131 has 4 divisors (see below), whose sum is σ = 54436614489192. Its totient is φ = 54391588335072.

The previous prime is 54414101412103. The next prime is 54414101412197. The reversal of 54414101412131 is 13121410141445.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54414101412131 - 214 = 54414101395747 is a prime.

It is a super-2 number, since 2×544141014121312 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54414101492131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11256534905 + ... + 11256539738.

It is an arithmetic number, because the mean of its divisors is an integer number (13609153622298).

Almost surely, 254414101412131 is an apocalyptic number.

54414101412131 is a deficient number, since it is larger than the sum of its proper divisors (22513077061).

54414101412131 is a wasteful number, since it uses less digits than its factorization.

54414101412131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22513077060.

The product of its (nonzero) digits is 7680, while the sum is 32.

Adding to 54414101412131 its reverse (13121410141445), we get a palindrome (67535511553576).

The spelling of 54414101412131 in words is "fifty-four trillion, four hundred fourteen billion, one hundred one million, four hundred twelve thousand, one hundred thirty-one".

Divisors: 1 2417 22513074643 54414101412131