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5442544364151 = 37949228227633
BaseRepresentation
bin100111100110011000011…
…1011000110101001110111
3201021022011021102010100210
41033030300323012221313
51203132312324123101
615324134222040503
71101132215535216
oct117146073065167
921238137363323
105442544364151
111809196452394
1273a975119133
133062ca94837b
1414b5c5dd507d
159688e1927d6
hex4f330ec6a77

5442544364151 has 8 divisors (see below), whose sum is σ = 7257638761200. Its totient is φ = 3627906438272.

The previous prime is 5442544364137. The next prime is 5442544364209. The reversal of 5442544364151 is 1514634452445.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5442544364151 - 210 = 5442544363127 is a prime.

It is a super-3 number, since 3×54425443641513 (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5442544364151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5442544164151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 114089970 + ... + 114137663.

It is an arithmetic number, because the mean of its divisors is an integer number (907204845150).

Almost surely, 25442544364151 is an apocalyptic number.

5442544364151 is a deficient number, since it is larger than the sum of its proper divisors (1815094397049).

5442544364151 is a wasteful number, since it uses less digits than its factorization.

5442544364151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 228235585.

The product of its digits is 4608000, while the sum is 48.

The spelling of 5442544364151 in words is "five trillion, four hundred forty-two billion, five hundred forty-four million, three hundred sixty-four thousand, one hundred fifty-one".

Divisors: 1 3 7949 23847 228227633 684682899 1814181454717 5442544364151