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54431455211311 = 269320212200227
BaseRepresentation
bin11000110000001010011111…
…00011010110111100101111
321010201121002200221122002011
430120011033203112330233
524113301110013230221
6311433244301542051
714315354126260543
oct1430051743267457
9233647080848064
1054431455211311
1116386283494962
126131220274927
13244ab308619c9
14d626d4519a23
15645d48c8b1e1
hex31814f8d6f2f

54431455211311 has 4 divisors (see below), whose sum is σ = 54451667414232. Its totient is φ = 54411243008392.

The previous prime is 54431455211297. The next prime is 54431455211417. The reversal of 54431455211311 is 11311255413445.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54431455211311 - 25 = 54431455211279 is a prime.

It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54431455218311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10106097421 + ... + 10106102806.

It is an arithmetic number, because the mean of its divisors is an integer number (13612916853558).

Almost surely, 254431455211311 is an apocalyptic number.

54431455211311 is a deficient number, since it is larger than the sum of its proper divisors (20212202921).

54431455211311 is a wasteful number, since it uses less digits than its factorization.

54431455211311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20212202920.

The product of its digits is 144000, while the sum is 40.

The spelling of 54431455211311 in words is "fifty-four trillion, four hundred thirty-one billion, four hundred fifty-five million, two hundred eleven thousand, three hundred eleven".

Divisors: 1 2693 20212200227 54431455211311