Base | Representation |
---|---|
bin | 11000110000001101100100… |
… | …11000001000110111010111 |
3 | 21010201202101020202220202211 |
4 | 30120012302120020313113 |
5 | 24113313003440330143 |
6 | 311434121010414251 |
7 | 14315443201130056 |
oct | 1430066230106727 |
9 | 233652336686684 |
10 | 54433113214423 |
11 | 16386a54383169 |
12 | 6131603591387 |
13 | 244b0361c5838 |
14 | d628107cc39d |
15 | 645de45e649d |
hex | 3181b2608dd7 |
54433113214423 has 4 divisors (see below), whose sum is σ = 54793597408048. Its totient is φ = 54072629020800.
The previous prime is 54433113214391. The next prime is 54433113214427. The reversal of 54433113214423 is 32441231133445.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54433113214423 - 25 = 54433113214391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54433113214427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180242096586 + ... + 180242096887.
It is an arithmetic number, because the mean of its divisors is an integer number (13698399352012).
Almost surely, 254433113214423 is an apocalyptic number.
54433113214423 is a deficient number, since it is larger than the sum of its proper divisors (360484193625).
54433113214423 is a wasteful number, since it uses less digits than its factorization.
54433113214423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 360484193624.
The product of its digits is 414720, while the sum is 40.
Adding to 54433113214423 its reverse (32441231133445), we get a palindrome (86874344347868).
The spelling of 54433113214423 in words is "fifty-four trillion, four hundred thirty-three billion, one hundred thirteen million, two hundred fourteen thousand, four hundred twenty-three".
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