Search a number
-
+
54433351309 = 371471171657
BaseRepresentation
bin110010101100011110…
…110000011010001101
312012111112221202022111
4302230132300122031
51342434414220214
641001211344021
73634623565141
oct625436603215
9165445852274
1054433351309
11210a3231557
12a671752011
1351963ac21c
1428c544b221
151638bba5c4
hexcac7b068d

54433351309 has 4 divisors (see below), whose sum is σ = 55904523004. Its totient is φ = 52962179616.

The previous prime is 54433351303. The next prime is 54433351319. The reversal of 54433351309 is 90315333445.

54433351309 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 35465175684 + 18968175625 = 188322^2 + 137725^2 .

It is a cyclic number.

It is not a de Polignac number, because 54433351309 - 213 = 54433343117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54433351303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 735585792 + ... + 735585865.

It is an arithmetic number, because the mean of its divisors is an integer number (13976130751).

Almost surely, 254433351309 is an apocalyptic number.

It is an amenable number.

54433351309 is a deficient number, since it is larger than the sum of its proper divisors (1471171695).

54433351309 is a wasteful number, since it uses less digits than its factorization.

54433351309 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1471171694.

The product of its (nonzero) digits is 291600, while the sum is 40.

The spelling of 54433351309 in words is "fifty-four billion, four hundred thirty-three million, three hundred fifty-one thousand, three hundred nine".

Divisors: 1 37 1471171657 54433351309