Base | Representation |
---|---|
bin | 11000110000011011001100… |
… | …01100100110001110000111 |
3 | 21010202110020211021220120012 |
4 | 30120031212030212032013 |
5 | 24113422442303230421 |
6 | 311441330324500435 |
7 | 14316122324552624 |
oct | 1430154614461607 |
9 | 233673224256505 |
10 | 54440425055111 |
11 | 1638a066759307 |
12 | 6132b0424a71b |
13 | 244b92ccb3ba4 |
14 | d62d0592134b |
15 | 6461c14ac95b |
hex | 318366326387 |
54440425055111 has 4 divisors (see below), whose sum is σ = 54440576895000. Its totient is φ = 54440273215224.
The previous prime is 54440425055101. The next prime is 54440425055141. The reversal of 54440425055111 is 11155052404445.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54440425055111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54440425055101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75380861 + ... + 76099638.
It is an arithmetic number, because the mean of its divisors is an integer number (13610144223750).
Almost surely, 254440425055111 is an apocalyptic number.
54440425055111 is a deficient number, since it is larger than the sum of its proper divisors (151839889).
54440425055111 is a wasteful number, since it uses less digits than its factorization.
54440425055111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151839888.
The product of its (nonzero) digits is 320000, while the sum is 41.
Adding to 54440425055111 its reverse (11155052404445), we get a palindrome (65595477459556).
The spelling of 54440425055111 in words is "fifty-four trillion, four hundred forty billion, four hundred twenty-five million, fifty-five thousand, one hundred eleven".
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