Base | Representation |
---|---|
bin | 11000110000011101100101… |
… | …10111010000011010000101 |
3 | 21010202120120110121020120211 |
4 | 30120032302313100122011 |
5 | 24113433111043300443 |
6 | 311442102113355421 |
7 | 14316166233531406 |
oct | 1430166267203205 |
9 | 233676513536524 |
10 | 54441711306373 |
11 | 1638a666815986 |
12 | 6133202b68b71 |
13 | 244baa6616c01 |
14 | d62dc86a39ad |
15 | 64624938419d |
hex | 3183b2dd0685 |
54441711306373 has 8 divisors (see below), whose sum is σ = 55255922435520. Its totient is φ = 53627548656000.
The previous prime is 54441711306361. The next prime is 54441711306379. The reversal of 54441711306373 is 37360311714445.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54441711306373 - 213 = 54441711298181 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54441711306379) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9853753 + ... + 14351998.
It is an arithmetic number, because the mean of its divisors is an integer number (6906990304440).
Almost surely, 254441711306373 is an apocalyptic number.
It is an amenable number.
54441711306373 is a deficient number, since it is larger than the sum of its proper divisors (814211129147).
54441711306373 is a wasteful number, since it uses less digits than its factorization.
54441711306373 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24239387.
The product of its (nonzero) digits is 2540160, while the sum is 49.
The spelling of 54441711306373 in words is "fifty-four trillion, four hundred forty-one billion, seven hundred eleven million, three hundred six thousand, three hundred seventy-three".
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