Base | Representation |
---|---|
bin | 100111100111010000110… |
… | …0001101010110101101111 |
3 | 201021111000221012021210011 |
4 | 1033032201201222311233 |
5 | 1203200144440201111 |
6 | 15325045505154051 |
7 | 1101230065240150 |
oct | 117164141526557 |
9 | 21244027167704 |
10 | 5444433522031 |
11 | 1809a75872699 |
12 | 73b20192b927 |
13 | 30653c153c7a |
14 | 14b724c79927 |
15 | 9694ee5d021 |
hex | 4f3a186ad6f |
5444433522031 has 16 divisors (see below), whose sum is σ = 6235881949440. Its totient is φ = 4656404269440.
The previous prime is 5444433522013. The next prime is 5444433522037. The reversal of 5444433522031 is 1302253344445.
It is not a de Polignac number, because 5444433522031 - 25 = 5444433521999 is a prime.
It is a super-2 number, since 2×54444335220312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5444433522037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 79006711 + ... + 79075591.
It is an arithmetic number, because the mean of its divisors is an integer number (389742621840).
Almost surely, 25444433522031 is an apocalyptic number.
5444433522031 is a deficient number, since it is larger than the sum of its proper divisors (791448427409).
5444433522031 is a wasteful number, since it uses less digits than its factorization.
5444433522031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93534.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 5444433522031 its reverse (1302253344445), we get a palindrome (6746686866476).
The spelling of 5444433522031 in words is "five trillion, four hundred forty-four billion, four hundred thirty-three million, five hundred twenty-two thousand, thirty-one".
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