Base | Representation |
---|---|
bin | 110010101101110001… |
… | …100011001110000011 |
3 | 12012120001210102111121 |
4 | 302231301203032003 |
5 | 1343010443231420 |
6 | 41003304453111 |
7 | 3635306221660 |
oct | 625561431603 |
9 | 165501712447 |
10 | 54455055235 |
11 | 21104505a89 |
12 | a678a7a197 |
13 | 519aa3b099 |
14 | 28c829aa67 |
15 | 163aa562aa |
hex | cadc63383 |
54455055235 has 32 divisors (see below), whose sum is σ = 77653204992. Its totient is φ = 35872208640.
The previous prime is 54455055233. The next prime is 54455055247. The reversal of 54455055235 is 53255055445.
54455055235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 54455055235 - 21 = 54455055233 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54455055191 and 54455055200.
It is not an unprimeable number, because it can be changed into a prime (54455055233) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34527 + ... + 331816.
It is an arithmetic number, because the mean of its divisors is an integer number (2426662656).
Almost surely, 254455055235 is an apocalyptic number.
54455055235 is a deficient number, since it is larger than the sum of its proper divisors (23198149757).
54455055235 is a wasteful number, since it uses less digits than its factorization.
54455055235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 366523.
The product of its (nonzero) digits is 1500000, while the sum is 43.
The spelling of 54455055235 in words is "fifty-four billion, four hundred fifty-five million, fifty-five thousand, two hundred thirty-five".
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