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545044306013 = 1531935579627
BaseRepresentation
bin1111110111001110010…
…11000001100001011101
31221002212002000112201122
413323213023001201131
532412222320243023
61054220115020325
754243464105564
oct7734713014135
91832762015648
10545044306013
111a0174335289
128977229a6a5
133c5222a269c
141c547706bdb
15e2a03c42c8
hex7ee72c185d

545044306013 has 4 divisors (see below), whose sum is σ = 545079900960. Its totient is φ = 545008711068.

The previous prime is 545044305991. The next prime is 545044306049. The reversal of 545044306013 is 310603440545.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-545044306013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (545044300013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17774495 + ... + 17805132.

It is an arithmetic number, because the mean of its divisors is an integer number (136269975240).

Almost surely, 2545044306013 is an apocalyptic number.

It is an amenable number.

545044306013 is a deficient number, since it is larger than the sum of its proper divisors (35594947).

545044306013 is a wasteful number, since it uses less digits than its factorization.

545044306013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35594946.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 545044306013 its reverse (310603440545), we get a palindrome (855647746558).

The spelling of 545044306013 in words is "five hundred forty-five billion, forty-four million, three hundred six thousand, thirteen".

Divisors: 1 15319 35579627 545044306013