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545401204053 = 3181800401351
BaseRepresentation
bin1111110111111000111…
…00011110110101010101
31221010202221120211210120
413323330130132311111
532413440202012203
61054315344342153
754255356512626
oct7737434366525
91833687524716
10545401204053
111a0337841042
1289851914959
133c57b202564
141c57cc8ba4d
15e2c18c1b53
hex7efc71ed55

545401204053 has 4 divisors (see below), whose sum is σ = 727201605408. Its totient is φ = 363600802700.

The previous prime is 545401204027. The next prime is 545401204057. The reversal of 545401204053 is 350402104545.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 545401204053 - 26 = 545401203989 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (545401204057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90900200673 + ... + 90900200678.

It is an arithmetic number, because the mean of its divisors is an integer number (181800401352).

Almost surely, 2545401204053 is an apocalyptic number.

It is an amenable number.

545401204053 is a deficient number, since it is larger than the sum of its proper divisors (181800401355).

545401204053 is a wasteful number, since it uses less digits than its factorization.

545401204053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 181800401354.

The product of its (nonzero) digits is 48000, while the sum is 33.

Adding to 545401204053 its reverse (350402104545), we get a palindrome (895803308598).

The spelling of 545401204053 in words is "five hundred forty-five billion, four hundred one million, two hundred four thousand, fifty-three".

Divisors: 1 3 181800401351 545401204053