Base | Representation |
---|---|
bin | 11000110110010101101010… |
… | …01110110111010110011101 |
3 | 21011110212201110002211010120 |
4 | 30123022311032313112131 |
5 | 24130240110303400131 |
6 | 312114532512025153 |
7 | 14336604464500425 |
oct | 1433126516672635 |
9 | 234425643084116 |
10 | 54643614512541 |
11 | 1645825492203a |
12 | 616636bb321b9 |
13 | 2464b42020082 |
14 | d6ca9d445485 |
15 | 64b61494b496 |
hex | 31b2b53b759d |
54643614512541 has 4 divisors (see below), whose sum is σ = 72858152683392. Its totient is φ = 36429076341692.
The previous prime is 54643614512537. The next prime is 54643614512569. The reversal of 54643614512541 is 14521541634645.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 54643614512541 - 22 = 54643614512537 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54643614512521) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9107269085421 + ... + 9107269085426.
It is an arithmetic number, because the mean of its divisors is an integer number (18214538170848).
Almost surely, 254643614512541 is an apocalyptic number.
It is an amenable number.
54643614512541 is a deficient number, since it is larger than the sum of its proper divisors (18214538170851).
54643614512541 is a wasteful number, since it uses less digits than its factorization.
54643614512541 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18214538170850.
The product of its digits is 6912000, while the sum is 51.
The spelling of 54643614512541 in words is "fifty-four trillion, six hundred forty-three billion, six hundred fourteen million, five hundred twelve thousand, five hundred forty-one".
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