Base | Representation |
---|---|
bin | 100111110011100101101… |
… | …1100001000100101011101 |
3 | 201101000100212210210222220 |
4 | 1033213023130020211131 |
5 | 1204113404032032403 |
6 | 15345144425255553 |
7 | 1103155110056040 |
oct | 117471334104535 |
9 | 21330325723886 |
10 | 5470906517853 |
11 | 181a220115237 |
12 | 74436b6345b9 |
13 | 308b9a8b623a |
14 | 14cb16ad6c57 |
15 | 9749e0e3953 |
hex | 4f9cb70895d |
5470906517853 has 16 divisors (see below), whose sum is σ = 8366287149696. Its totient is φ = 3115106910720.
The previous prime is 5470906517851. The next prime is 5470906517861. The reversal of 5470906517853 is 3587156090745.
It is not a de Polignac number, because 5470906517853 - 21 = 5470906517851 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5470906517851) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 463551676 + ... + 463563477.
It is an arithmetic number, because the mean of its divisors is an integer number (522892946856).
Almost surely, 25470906517853 is an apocalyptic number.
It is an amenable number.
5470906517853 is a deficient number, since it is larger than the sum of its proper divisors (2895380631843).
5470906517853 is a wasteful number, since it uses less digits than its factorization.
5470906517853 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 927115444.
The product of its (nonzero) digits is 31752000, while the sum is 60.
The spelling of 5470906517853 in words is "five trillion, four hundred seventy billion, nine hundred six million, five hundred seventeen thousand, eight hundred fifty-three".
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