Base | Representation |
---|---|
bin | 1010001100001111… |
… | …10111111010011101 |
3 | 112010022110202210021 |
4 | 11012013313322131 |
5 | 42201141431240 |
6 | 2302531512141 |
7 | 252405304516 |
oct | 50607677235 |
9 | 15108422707 |
10 | 5471436445 |
11 | 2358535202 |
12 | 1088458651 |
13 | 692722777 |
14 | 39c93da0d |
15 | 22052b54a |
hex | 1461f7e9d |
5471436445 has 4 divisors (see below), whose sum is σ = 6565723740. Its totient is φ = 4377149152.
The previous prime is 5471436389. The next prime is 5471436463. The reversal of 5471436445 is 5446341745.
5471436445 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3913002916 + 1558433529 = 62554^2 + 39477^2 .
It is a cyclic number.
It is not a de Polignac number, because 5471436445 - 27 = 5471436317 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 547143640 + ... + 547143649.
It is an arithmetic number, because the mean of its divisors is an integer number (1641430935).
Almost surely, 25471436445 is an apocalyptic number.
It is an amenable number.
5471436445 is a deficient number, since it is larger than the sum of its proper divisors (1094287295).
5471436445 is a wasteful number, since it uses less digits than its factorization.
5471436445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1094287294.
The product of its digits is 806400, while the sum is 43.
The square root of 5471436445 is about 73969.1587420054. The cubic root of 5471436445 is about 1762.1131261588.
The spelling of 5471436445 in words is "five billion, four hundred seventy-one million, four hundred thirty-six thousand, four hundred forty-five".
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