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5473134677253 = 31824378225751
BaseRepresentation
bin100111110100101000000…
…1111111000110100000101
3201101020010011111001002010
41033221100033320310011
51204132434434133003
615350153502404433
71103264244106425
oct117512017706405
921336104431063
105473134677253
111820163928391
12744891890719
133091643c6b59
1414cc889c4485
159757ea24003
hex4fa503f8d05

5473134677253 has 4 divisors (see below), whose sum is σ = 7297512903008. Its totient is φ = 3648756451500.

The previous prime is 5473134677251. The next prime is 5473134677281. The reversal of 5473134677253 is 3527764313745.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5473134677253 - 21 = 5473134677251 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5473134677193 and 5473134677202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5473134677251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 912189112873 + ... + 912189112878.

It is an arithmetic number, because the mean of its divisors is an integer number (1824378225752).

Almost surely, 25473134677253 is an apocalyptic number.

It is an amenable number.

5473134677253 is a deficient number, since it is larger than the sum of its proper divisors (1824378225755).

5473134677253 is a wasteful number, since it uses less digits than its factorization.

5473134677253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1824378225754.

The product of its digits is 44452800, while the sum is 57.

The spelling of 5473134677253 in words is "five trillion, four hundred seventy-three billion, one hundred thirty-four million, six hundred seventy-seven thousand, two hundred fifty-three".

Divisors: 1 3 1824378225751 5473134677253