Base | Representation |
---|---|
bin | 11000111001110111011000… |
… | …11011110110001010111001 |
3 | 21011220110112001111120022010 |
4 | 30130323230123312022321 |
5 | 24134231302213343440 |
6 | 312250333544120133 |
7 | 14351424535132224 |
oct | 1434735433661271 |
9 | 234813461446263 |
10 | 54764799746745 |
11 | 164a4691818160 |
12 | 6185950766049 |
13 | 24733b592ba4a |
14 | d748b7d565bb |
15 | 64e8589c2580 |
hex | 31ceec6f62b9 |
54764799746745 has 64 divisors (see below), whose sum is σ = 98605450331136. Its totient is φ = 25721180340480.
The previous prime is 54764799746689. The next prime is 54764799746747.
54764799746745 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 54764799746745 - 231 = 54762652263097 is a prime.
It is a super-3 number, since 3×547647997467453 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (54764799746747) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 18372939 + ... + 21144608.
It is an arithmetic number, because the mean of its divisors is an integer number (1540710161424).
Almost surely, 254764799746745 is an apocalyptic number.
54764799746745 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54764799746745 is a deficient number, since it is larger than the sum of its proper divisors (43840650584391).
54764799746745 is a wasteful number, since it uses less digits than its factorization.
54764799746745 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39517830.
The product of its digits is 44808422400, while the sum is 84.
The spelling of 54764799746745 in words is "fifty-four trillion, seven hundred sixty-four billion, seven hundred ninety-nine million, seven hundred forty-six thousand, seven hundred forty-five".
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