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54939140253 = 329916159787
BaseRepresentation
bin110011001010101000…
…001100000010011101
312020210210200111022100
4303022220030002131
51400003404442003
641123320235313
73653304662364
oct631250140235
9166723614270
1054939140253
1121332792248
12a79300bb39
13524711021a
1429326ac7db
1516682c8ba3
hexccaa0c09d

54939140253 has 12 divisors (see below), whose sum is σ = 79436626048. Its totient is φ = 36589128840.

The previous prime is 54939140239. The next prime is 54939140257. The reversal of 54939140253 is 35204193945.

54939140253 is a `hidden beast` number, since 5 + 4 + 9 + 391 + 4 + 0 + 253 = 666.

It is not a de Polignac number, because 54939140253 - 24 = 54939140237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 54939140199 and 54939140208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54939140257) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3070975 + ... + 3088812.

Almost surely, 254939140253 is an apocalyptic number.

It is an amenable number.

54939140253 is a deficient number, since it is larger than the sum of its proper divisors (24497485795).

54939140253 is a wasteful number, since it uses less digits than its factorization.

54939140253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6160784 (or 6160781 counting only the distinct ones).

The product of its (nonzero) digits is 583200, while the sum is 45.

The spelling of 54939140253 in words is "fifty-four billion, nine hundred thirty-nine million, one hundred forty thousand, two hundred fifty-three".

Divisors: 1 3 9 991 2973 8919 6159787 18479361 55438083 6104348917 18313046751 54939140253