Base | Representation |
---|---|
bin | 110011001110010000… |
… | …011001010101100101 |
3 | 12020222001020002211102 |
4 | 303032100121111211 |
5 | 1400120000342013 |
6 | 41133333045445 |
7 | 3654644250413 |
oct | 631620312545 |
9 | 166861202742 |
10 | 55000012133 |
11 | 21364089190 |
12 | a7ab486885 |
13 | 5256903ca1 |
14 | 293a7d62b3 |
15 | 166d7eed58 |
hex | cce419565 |
55000012133 has 4 divisors (see below), whose sum is σ = 60000013248. Its totient is φ = 50000011020.
The previous prime is 55000012121. The next prime is 55000012153. The reversal of 55000012133 is 33121000055.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55000012133 - 230 = 53926270309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55000012153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2500000541 + ... + 2500000562.
It is an arithmetic number, because the mean of its divisors is an integer number (15000003312).
Almost surely, 255000012133 is an apocalyptic number.
It is an amenable number.
55000012133 is a deficient number, since it is larger than the sum of its proper divisors (5000001115).
55000012133 is a wasteful number, since it uses less digits than its factorization.
55000012133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5000001114.
The product of its (nonzero) digits is 450, while the sum is 20.
Adding to 55000012133 its reverse (33121000055), we get a palindrome (88121012188).
The spelling of 55000012133 in words is "fifty-five billion, twelve thousand, one hundred thirty-three".
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