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55000012133 = 115000001103
BaseRepresentation
bin110011001110010000…
…011001010101100101
312020222001020002211102
4303032100121111211
51400120000342013
641133333045445
73654644250413
oct631620312545
9166861202742
1055000012133
1121364089190
12a7ab486885
135256903ca1
14293a7d62b3
15166d7eed58
hexcce419565

55000012133 has 4 divisors (see below), whose sum is σ = 60000013248. Its totient is φ = 50000011020.

The previous prime is 55000012121. The next prime is 55000012153. The reversal of 55000012133 is 33121000055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55000012133 - 230 = 53926270309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55000012153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2500000541 + ... + 2500000562.

It is an arithmetic number, because the mean of its divisors is an integer number (15000003312).

Almost surely, 255000012133 is an apocalyptic number.

It is an amenable number.

55000012133 is a deficient number, since it is larger than the sum of its proper divisors (5000001115).

55000012133 is a wasteful number, since it uses less digits than its factorization.

55000012133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5000001114.

The product of its (nonzero) digits is 450, while the sum is 20.

Adding to 55000012133 its reverse (33121000055), we get a palindrome (88121012188).

The spelling of 55000012133 in words is "fifty-five billion, twelve thousand, one hundred thirty-three".

Divisors: 1 11 5000001103 55000012133