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55000120133 = 723341615653
BaseRepresentation
bin110011001110010000…
…110011101101000101
312020222001102120222102
4303032100303231011
51400120012321013
641133335241445
73654645210320
oct631620635505
9166861376872
1055000120133
1121364152342
12a7ab519285
1352569411aa
14293a8237b7
15166d821d58
hexcce433b45

55000120133 has 8 divisors (see below), whose sum is σ = 65590205568. Its totient is φ = 45093266064.

The previous prime is 55000120099. The next prime is 55000120157. The reversal of 55000120133 is 33102100055.

55000120133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 55000120133 - 28 = 55000119877 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55000120163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 170807666 + ... + 170807987.

It is an arithmetic number, because the mean of its divisors is an integer number (8198775696).

Almost surely, 255000120133 is an apocalyptic number.

It is an amenable number.

55000120133 is a deficient number, since it is larger than the sum of its proper divisors (10590085435).

55000120133 is a wasteful number, since it uses less digits than its factorization.

55000120133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 341615683.

The product of its (nonzero) digits is 450, while the sum is 20.

Adding to 55000120133 its reverse (33102100055), we get a palindrome (88102220188).

The spelling of 55000120133 in words is "fifty-five billion, one hundred twenty thousand, one hundred thirty-three".

Divisors: 1 7 23 161 341615653 2391309571 7857160019 55000120133