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55000503401 = 131419851171
BaseRepresentation
bin110011001110010010…
…010001010001101001
312020222002011001201112
4303032102101101221
51400120112102101
641133351400105
73654651364604
oct631622212151
9166862131645
1055000503401
1121364394298
12a7ab683035
135256a4678c
14293a8c333b
15166d89a6bb
hexcce491469

55000503401 has 4 divisors (see below), whose sum is σ = 55420354704. Its totient is φ = 54580652100.

The previous prime is 55000503347. The next prime is 55000503433. The reversal of 55000503401 is 10430500055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10430500055 = 52086100011.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55000503401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55000505401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209925455 + ... + 209925716.

It is an arithmetic number, because the mean of its divisors is an integer number (13855088676).

Almost surely, 255000503401 is an apocalyptic number.

It is an amenable number.

55000503401 is a deficient number, since it is larger than the sum of its proper divisors (419851303).

55000503401 is a wasteful number, since it uses less digits than its factorization.

55000503401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 419851302.

The product of its (nonzero) digits is 1500, while the sum is 23.

The spelling of 55000503401 in words is "fifty-five billion, five hundred three thousand, four hundred one".

Divisors: 1 131 419851171 55000503401