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550006393901 = 3716561897593
BaseRepresentation
bin10000000000011101110…
…11111000110000101101
31221120122220001201122112
420000032323320300231
533002403114101101
61100400333453405
754510446132246
oct10001673706055
91846586051575
10550006393901
111a22902a8368
128a718041265
133cb33318b73
141c898739ccd
15e490d3c6bb
hex800eef8c2d

550006393901 has 8 divisors (see below), whose sum is σ = 564906169464. Its totient is φ = 535108446720.

The previous prime is 550006393877. The next prime is 550006393903. The reversal of 550006393901 is 109393600055.

It can be written as a sum of positive squares in 4 ways, for example, as 225705757225 + 324300636676 = 475085^2 + 569474^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 550006393901 - 218 = 550006131757 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (550006393903) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 163961 + ... + 1061553.

It is an arithmetic number, because the mean of its divisors is an integer number (70613271183).

Almost surely, 2550006393901 is an apocalyptic number.

It is an amenable number.

550006393901 is a deficient number, since it is larger than the sum of its proper divisors (14899775563).

550006393901 is a wasteful number, since it uses less digits than its factorization.

550006393901 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 914191.

The product of its (nonzero) digits is 109350, while the sum is 41.

Adding to 550006393901 its reverse (109393600055), we get a palindrome (659399993956).

The spelling of 550006393901 in words is "five hundred fifty billion, six million, three hundred ninety-three thousand, nine hundred one".

Divisors: 1 37 16561 612757 897593 33210941 14865037673 550006393901