Base | Representation |
---|---|
bin | 10000000000011101110… |
… | …11111000110000101101 |
3 | 1221120122220001201122112 |
4 | 20000032323320300231 |
5 | 33002403114101101 |
6 | 1100400333453405 |
7 | 54510446132246 |
oct | 10001673706055 |
9 | 1846586051575 |
10 | 550006393901 |
11 | 1a22902a8368 |
12 | 8a718041265 |
13 | 3cb33318b73 |
14 | 1c898739ccd |
15 | e490d3c6bb |
hex | 800eef8c2d |
550006393901 has 8 divisors (see below), whose sum is σ = 564906169464. Its totient is φ = 535108446720.
The previous prime is 550006393877. The next prime is 550006393903. The reversal of 550006393901 is 109393600055.
It can be written as a sum of positive squares in 4 ways, for example, as 225705757225 + 324300636676 = 475085^2 + 569474^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 550006393901 - 218 = 550006131757 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (550006393903) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 163961 + ... + 1061553.
It is an arithmetic number, because the mean of its divisors is an integer number (70613271183).
Almost surely, 2550006393901 is an apocalyptic number.
It is an amenable number.
550006393901 is a deficient number, since it is larger than the sum of its proper divisors (14899775563).
550006393901 is a wasteful number, since it uses less digits than its factorization.
550006393901 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 914191.
The product of its (nonzero) digits is 109350, while the sum is 41.
Adding to 550006393901 its reverse (109393600055), we get a palindrome (659399993956).
The spelling of 550006393901 in words is "five hundred fifty billion, six million, three hundred ninety-three thousand, nine hundred one".
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