Base | Representation |
---|---|
bin | 101000000001001110110… |
… | …1011011101101000000111 |
3 | 201110210222122100112002012 |
4 | 1100002131223131220013 |
5 | 1210103404102232320 |
6 | 15410431510404435 |
7 | 1105243112554346 |
oct | 120023553355007 |
9 | 21423878315065 |
10 | 5500203555335 |
11 | 1830694576105 |
12 | 749b8706071b |
13 | 30b889442688 |
14 | 1502d5a35b5d |
15 | 981161624c5 |
hex | 5009dadda07 |
5500203555335 has 16 divisors (see below), whose sum is σ = 6614836794720. Its totient is φ = 4390435290240.
The previous prime is 5500203555239. The next prime is 5500203555347. The reversal of 5500203555335 is 5335553020055.
It is not a de Polignac number, because 5500203555335 - 242 = 1102157044231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5500203555292 and 5500203555301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 93874109 + ... + 93932681.
It is an arithmetic number, because the mean of its divisors is an integer number (413427299670).
Almost surely, 25500203555335 is an apocalyptic number.
5500203555335 is a deficient number, since it is larger than the sum of its proper divisors (1114633239385).
5500203555335 is a wasteful number, since it uses less digits than its factorization.
5500203555335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99778.
The product of its (nonzero) digits is 843750, while the sum is 41.
The spelling of 5500203555335 in words is "five trillion, five hundred billion, two hundred three million, five hundred fifty-five thousand, three hundred thirty-five".
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