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55003027999 = 121697451967
BaseRepresentation
bin110011001110011011…
…111001101000011111
312020222020220022211011
4303032123321220133
51400121233343444
641133521440051
73655012011133
oct631633715037
9166866808734
1055003027999
1121365859037
12a7b04a0027
13525741b91a
14293ad7d3c3
15166dbe8734
hexcce6f9a1f

55003027999 has 4 divisors (see below), whose sum is σ = 55003601664. Its totient is φ = 55002454336.

The previous prime is 55003027969. The next prime is 55003028027. The reversal of 55003027999 is 99972030055.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 99972030055 = 519994406011.

It is a cyclic number.

It is not a de Polignac number, because 55003027999 - 221 = 55000930847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55003027909) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104287 + ... + 347680.

It is an arithmetic number, because the mean of its divisors is an integer number (13750900416).

Almost surely, 255003027999 is an apocalyptic number.

55003027999 is a deficient number, since it is larger than the sum of its proper divisors (573665).

55003027999 is a wasteful number, since it uses less digits than its factorization.

55003027999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 573664.

The product of its (nonzero) digits is 765450, while the sum is 49.

The spelling of 55003027999 in words is "fifty-five billion, three million, twenty-seven thousand, nine hundred ninety-nine".

Divisors: 1 121697 451967 55003027999