Base | Representation |
---|---|
bin | 110011001110011100… |
… | …010001101101110101 |
3 | 12020222021002100010201 |
4 | 303032130101231311 |
5 | 1400121300023040 |
6 | 41133523520501 |
7 | 3655012601545 |
oct | 631634215565 |
9 | 166867070121 |
10 | 55003126645 |
11 | 21365916165 |
12 | a7b0529131 |
13 | 52574547ac |
14 | 293ada7325 |
15 | 166dc17a9a |
hex | cce711b75 |
55003126645 has 4 divisors (see below), whose sum is σ = 66003751980. Its totient is φ = 44002501312.
The previous prime is 55003126643. The next prime is 55003126681. The reversal of 55003126645 is 54662130055.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 31767002289 + 23236124356 = 178233^2 + 152434^2 .
It is a cyclic number.
It is not a de Polignac number, because 55003126645 - 21 = 55003126643 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55003126643) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5500312660 + ... + 5500312669.
It is an arithmetic number, because the mean of its divisors is an integer number (16500937995).
Almost surely, 255003126645 is an apocalyptic number.
It is an amenable number.
55003126645 is a deficient number, since it is larger than the sum of its proper divisors (11000625335).
55003126645 is a wasteful number, since it uses less digits than its factorization.
55003126645 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11000625334.
The product of its (nonzero) digits is 108000, while the sum is 37.
The spelling of 55003126645 in words is "fifty-five billion, three million, one hundred twenty-six thousand, six hundred forty-five".
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