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550031707121 = 1342310131317
BaseRepresentation
bin10000000000100000111…
…00011100101111110001
31221120201122200202212012
420000100130130233301
533002431104111441
61100403040212305
754511204240601
oct10002034345761
91846648622765
10550031707121
111a22a3617586
128a72460a095
133cb3863c7c0
141c89bc48c01
15e49318c9eb
hex801071cbf1

550031707121 has 4 divisors (see below), whose sum is σ = 592341838452. Its totient is φ = 507721575792.

The previous prime is 550031707111. The next prime is 550031707153. The reversal of 550031707121 is 121707130055.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 66574320400 + 483457386721 = 258020^2 + 695311^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-550031707121 is a prime.

It is not an unprimeable number, because it can be changed into a prime (550031707111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21155065646 + ... + 21155065671.

It is an arithmetic number, because the mean of its divisors is an integer number (148085459613).

Almost surely, 2550031707121 is an apocalyptic number.

It is an amenable number.

550031707121 is a deficient number, since it is larger than the sum of its proper divisors (42310131331).

550031707121 is a wasteful number, since it uses less digits than its factorization.

550031707121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42310131330.

The product of its (nonzero) digits is 7350, while the sum is 32.

Adding to 550031707121 its reverse (121707130055), we get a palindrome (671738837176).

The spelling of 550031707121 in words is "five hundred fifty billion, thirty-one million, seven hundred seven thousand, one hundred twenty-one".

Divisors: 1 13 42310131317 550031707121